Base | Representation |
---|---|
bin | 1100110111000… |
… | …1001111010111 |
3 | 10202111111102111 |
4 | 3031301033113 |
5 | 102302104312 |
6 | 5204051451 |
7 | 1223330665 |
oct | 315611727 |
9 | 122444374 |
10 | 53941207 |
11 | 284a2911 |
12 | 16093b87 |
13 | b238298 |
14 | 7241c35 |
15 | 4b078a7 |
hex | 33713d7 |
53941207 has 2 divisors, whose sum is σ = 53941208. Its totient is φ = 53941206.
The previous prime is 53941201. The next prime is 53941211. The reversal of 53941207 is 70214935.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53941207 - 219 = 53416919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53941201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26970603 + 26970604.
It is an arithmetic number, because the mean of its divisors is an integer number (26970604).
Almost surely, 253941207 is an apocalyptic number.
53941207 is a deficient number, since it is larger than the sum of its proper divisors (1).
53941207 is an equidigital number, since it uses as much as digits as its factorization.
53941207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
The square root of 53941207 is about 7344.4677819431. The cubic root of 53941207 is about 377.8390900839.
The spelling of 53941207 in words is "fifty-three million, nine hundred forty-one thousand, two hundred seven".
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