Base | Representation |
---|---|
bin | 1111101100110101101… |
… | …10111000101101100011 |
3 | 1220120110112002012210021 |
4 | 13312122312320231203 |
5 | 32314313030210311 |
6 | 1051454552414311 |
7 | 53655354524044 |
oct | 7663266705543 |
9 | 1816415065707 |
10 | 539468991331 |
11 | 1988731aa8a6 |
12 | 886770a7397 |
13 | 3bb441ac10a |
14 | 1c1790868cb |
15 | e075bc9171 |
hex | 7d9adb8b63 |
539468991331 has 2 divisors, whose sum is σ = 539468991332. Its totient is φ = 539468991330.
The previous prime is 539468991329. The next prime is 539468991379. The reversal of 539468991331 is 133199864935.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 539468991331 - 21 = 539468991329 is a prime.
It is a super-2 number, since 2×5394689913312 (a number of 24 digits) contains 22 as substring.
Together with 539468991329, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 539468991331.
It is not a weakly prime, because it can be changed into another prime (539468971331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 269734495665 + 269734495666.
It is an arithmetic number, because the mean of its divisors is an integer number (269734495666).
Almost surely, 2539468991331 is an apocalyptic number.
539468991331 is a deficient number, since it is larger than the sum of its proper divisors (1).
539468991331 is an equidigital number, since it uses as much as digits as its factorization.
539468991331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18895680, while the sum is 61.
The spelling of 539468991331 in words is "five hundred thirty-nine billion, four hundred sixty-eight million, nine hundred ninety-one thousand, three hundred thirty-one".
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