Base | Representation |
---|---|
bin | 110010010001000110… |
… | …001010100110011001 |
3 | 12011022112110020020202 |
4 | 302101012022212121 |
5 | 1341014310421103 |
6 | 40443440231545 |
7 | 3620344515536 |
oct | 622106124631 |
9 | 164275406222 |
10 | 53973920153 |
11 | 2098796408a |
12 | a56390b5b5 |
13 | 512215c87a |
14 | 2880415d8d |
15 | 160d6b7988 |
hex | c9118a999 |
53973920153 has 4 divisors (see below), whose sum is σ = 54179144448. Its totient is φ = 53768695860.
The previous prime is 53973920129. The next prime is 53973920159. The reversal of 53973920153 is 35102937935.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53973920153 - 214 = 53973903769 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53973920098 and 53973920107.
It is not an unprimeable number, because it can be changed into a prime (53973920159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102611753 + ... + 102612278.
It is an arithmetic number, because the mean of its divisors is an integer number (13544786112).
Almost surely, 253973920153 is an apocalyptic number.
It is an amenable number.
53973920153 is a deficient number, since it is larger than the sum of its proper divisors (205224295).
53973920153 is a wasteful number, since it uses less digits than its factorization.
53973920153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 205224294.
The product of its (nonzero) digits is 765450, while the sum is 47.
The spelling of 53973920153 in words is "fifty-three billion, nine hundred seventy-three million, nine hundred twenty thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •