Base | Representation |
---|---|
bin | 100111010010101101100… |
… | …1010010001100111110001 |
3 | 201010021010102102022100112 |
4 | 1032211123022101213301 |
5 | 1201434310121430340 |
6 | 15252510505431105 |
7 | 1065105356523605 |
oct | 116453312214761 |
9 | 21107112368315 |
10 | 5400303311345 |
11 | 17a228a485198 |
12 | 73274679b495 |
13 | 3023284bc677 |
14 | 149539d41505 |
15 | 9571aa80065 |
hex | 4e95b2919f1 |
5400303311345 has 4 divisors (see below), whose sum is σ = 6480363973620. Its totient is φ = 4320242649072.
The previous prime is 5400303311329. The next prime is 5400303311419. The reversal of 5400303311345 is 5431133030045.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1081649920576 + 4318653390769 = 1040024^2 + 2078137^2 .
It is a cyclic number.
It is not a de Polignac number, because 5400303311345 - 24 = 5400303311329 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 540030331130 + ... + 540030331139.
It is an arithmetic number, because the mean of its divisors is an integer number (1620090993405).
Almost surely, 25400303311345 is an apocalyptic number.
It is an amenable number.
5400303311345 is a deficient number, since it is larger than the sum of its proper divisors (1080060662275).
5400303311345 is a wasteful number, since it uses less digits than its factorization.
5400303311345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1080060662274.
The product of its (nonzero) digits is 32400, while the sum is 32.
The spelling of 5400303311345 in words is "five trillion, four hundred billion, three hundred three million, three hundred eleven thousand, three hundred forty-five".
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