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540100113551 = 4312560467757
BaseRepresentation
bin1111101110000000111…
…10011011010010001111
31220122002111122112201022
413313000132123102033
532322111112113201
61052041335504355
754010120134365
oct7670036332217
91818074575638
10540100113551
11199067485309
12888125280bb
133bc14b8370b
141c1d8c11635
15e0b12e341b
hex7dc079b48f

540100113551 has 4 divisors (see below), whose sum is σ = 552660581352. Its totient is φ = 527539645752.

The previous prime is 540100113547. The next prime is 540100113557. The reversal of 540100113551 is 155311001045.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 540100113551 - 22 = 540100113547 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 540100113551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (540100113557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6280233836 + ... + 6280233921.

It is an arithmetic number, because the mean of its divisors is an integer number (138165145338).

Almost surely, 2540100113551 is an apocalyptic number.

540100113551 is a deficient number, since it is larger than the sum of its proper divisors (12560467801).

540100113551 is a wasteful number, since it uses less digits than its factorization.

540100113551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12560467800.

The product of its (nonzero) digits is 1500, while the sum is 26.

Adding to 540100113551 its reverse (155311001045), we get a palindrome (695411114596).

The spelling of 540100113551 in words is "five hundred forty billion, one hundred million, one hundred thirteen thousand, five hundred fifty-one".

Divisors: 1 43 12560467757 540100113551