Base | Representation |
---|---|
bin | 100000001100011… |
… | …001010001010111 |
3 | 1101122022221120001 |
4 | 200030121101113 |
5 | 2101232321101 |
6 | 125332352131 |
7 | 16245642214 |
oct | 4014312127 |
9 | 1348287501 |
10 | 540120151 |
11 | 25797a29a |
12 | 130a75647 |
13 | 87b9152c |
14 | 51a3ab0b |
15 | 32640901 |
hex | 20319457 |
540120151 has 2 divisors, whose sum is σ = 540120152. Its totient is φ = 540120150.
The previous prime is 540120137. The next prime is 540120181. The reversal of 540120151 is 151021045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 540120151 - 29 = 540119639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540120181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270060075 + 270060076.
It is an arithmetic number, because the mean of its divisors is an integer number (270060076).
Almost surely, 2540120151 is an apocalyptic number.
540120151 is a deficient number, since it is larger than the sum of its proper divisors (1).
540120151 is an equidigital number, since it uses as much as digits as its factorization.
540120151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 200, while the sum is 19.
The square root of 540120151 is about 23240.4851713556. The cubic root of 540120151 is about 814.3856767942.
Adding to 540120151 its reverse (151021045), we get a palindrome (691141196).
It can be divided in two parts, 5401 and 20151, that added together give a palindrome (25552).
The spelling of 540120151 in words is "five hundred forty million, one hundred twenty thousand, one hundred fifty-one".
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