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5401314413207 is a prime number
BaseRepresentation
bin100111010011001011101…
…1011010100101010010111
3201010100201212222121100122
41032212113123110222113
51201443342442210312
615253155105102155
71065142414663466
oct116462733245227
921110655877318
105401314413207
1117a27591a0a69
1273298932795b
13302459b15aab
141495d433c9dd
1595779705b72
hex4e9976d4a97

5401314413207 has 2 divisors, whose sum is σ = 5401314413208. Its totient is φ = 5401314413206.

The previous prime is 5401314413189. The next prime is 5401314413219. The reversal of 5401314413207 is 7023144131045.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5401314413207 - 28 = 5401314412951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5401314413237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2700657206603 + 2700657206604.

It is an arithmetic number, because the mean of its divisors is an integer number (2700657206604).

Almost surely, 25401314413207 is an apocalyptic number.

5401314413207 is a deficient number, since it is larger than the sum of its proper divisors (1).

5401314413207 is an equidigital number, since it uses as much as digits as its factorization.

5401314413207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 35.

The spelling of 5401314413207 in words is "five trillion, four hundred one billion, three hundred fourteen million, four hundred thirteen thousand, two hundred seven".