Base | Representation |
---|---|
bin | 100111010011001100001… |
… | …1011011110011011110111 |
3 | 201010100210001122000021200 |
4 | 1032212120123132123313 |
5 | 1201443411243333310 |
6 | 15253200505343543 |
7 | 1065143010635406 |
oct | 116463033363367 |
9 | 21110701560250 |
10 | 5401331230455 |
11 | 17a2767738016 |
12 | 732992a97bb3 |
13 | 302460453624 |
14 | 1495d667963d |
15 | 9577ae289c0 |
hex | 4e9986de6f7 |
5401331230455 has 96 divisors (see below), whose sum is σ = 9790622779392. Its totient is φ = 2751417504000.
The previous prime is 5401331230447. The next prime is 5401331230457. The reversal of 5401331230455 is 5540321331045.
5401331230455 is a `hidden beast` number, since 5 + 40 + 1 + 331 + 230 + 4 + 55 = 666.
It is not a de Polignac number, because 5401331230455 - 23 = 5401331230447 is a prime.
It is a super-2 number, since 2×54013312304552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5401331230457) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 117267180 + ... + 117313230.
It is an arithmetic number, because the mean of its divisors is an integer number (101985653952).
Almost surely, 25401331230455 is an apocalyptic number.
5401331230455 is a deficient number, since it is larger than the sum of its proper divisors (4389291548937).
5401331230455 is a wasteful number, since it uses less digits than its factorization.
5401331230455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47189 (or 47186 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
The spelling of 5401331230455 in words is "five trillion, four hundred one billion, three hundred thirty-one million, two hundred thirty thousand, four hundred fifty-five".
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