Base | Representation |
---|---|
bin | 110010010011011100… |
… | …110100001011001001 |
3 | 12011102021202121221021 |
4 | 302103130310023021 |
5 | 1341104413141131 |
6 | 40451410512441 |
7 | 3621334266331 |
oct | 622334641311 |
9 | 164367677837 |
10 | 54013412041 |
11 | 209a8187a06 |
12 | a574b95721 |
13 | 512a3a9054 |
14 | 28857760c1 |
15 | 1611db8e11 |
hex | c937342c9 |
54013412041 has 2 divisors, whose sum is σ = 54013412042. Its totient is φ = 54013412040.
The previous prime is 54013411987. The next prime is 54013412053. The reversal of 54013412041 is 14021431045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51804036025 + 2209376016 = 227605^2 + 47004^2 .
It is a cyclic number.
It is not a de Polignac number, because 54013412041 - 225 = 53979857609 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54013411997 and 54013412015.
It is not a weakly prime, because it can be changed into another prime (54013412441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27006706020 + 27006706021.
It is an arithmetic number, because the mean of its divisors is an integer number (27006706021).
Almost surely, 254013412041 is an apocalyptic number.
It is an amenable number.
54013412041 is a deficient number, since it is larger than the sum of its proper divisors (1).
54013412041 is an equidigital number, since it uses as much as digits as its factorization.
54013412041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 54013412041 its reverse (14021431045), we get a palindrome (68034843086).
The spelling of 54013412041 in words is "fifty-four billion, thirteen million, four hundred twelve thousand, forty-one".
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