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54014310503 = 3147136127239
BaseRepresentation
bin110010010011100000…
…001111100001100111
312011102100110021101122
4302103200033201213
51341110130414003
640451442044155
73621345030626
oct622340174147
9164370407348
1054014310503
11209a8740a3a
12a57534965b
13512a631c9a
14288592b6bd
151611ee5238
hexc9380f867

54014310503 has 16 divisors (see below), whose sum is σ = 56986951680. Its totient is φ = 51120278400.

The previous prime is 54014310481. The next prime is 54014310533. The reversal of 54014310503 is 30501341045.

It is a cyclic number.

It is not a de Polignac number, because 54014310503 - 28 = 54014310247 is a prime.

It is a super-2 number, since 2×540143105032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54014310533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1969358 + ... + 1996596.

It is an arithmetic number, because the mean of its divisors is an integer number (3561684480).

Almost surely, 254014310503 is an apocalyptic number.

54014310503 is a deficient number, since it is larger than the sum of its proper divisors (2972641177).

54014310503 is a wasteful number, since it uses less digits than its factorization.

54014310503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28678.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 54014310503 its reverse (30501341045), we get a palindrome (84515651548).

The spelling of 54014310503 in words is "fifty-four billion, fourteen million, three hundred ten thousand, five hundred three".

Divisors: 1 31 47 1361 1457 27239 42191 63967 844409 1280233 1982977 37072279 39687223 1149240649 1742397113 54014310503