Base | Representation |
---|---|
bin | 111101011010000100001010… |
… | …0100101101110111001101111 |
3 | 2121211111021010122021111010202 |
4 | 1322310020110211232321233 |
5 | 1031244204424230442221 |
6 | 5152442423252224115 |
7 | 221526055261300544 |
oct | 17264102445567157 |
9 | 2554437118244122 |
10 | 540144022515311 |
11 | 1471198802032a5 |
12 | 506b764430b03b |
13 | 1a251493cc60c6 |
14 | 9755178498bcb |
15 | 426a5bb55cd0b |
hex | 1eb421496ee6f |
540144022515311 has 16 divisors (see below), whose sum is σ = 565245057611520. Its totient is φ = 515177799502080.
The previous prime is 540144022515271. The next prime is 540144022515337. The reversal of 540144022515311 is 113515220441045.
It is a de Polignac number, because none of the positive numbers 2k-540144022515311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (540144027515311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 233153576 + ... + 235458866.
It is an arithmetic number, because the mean of its divisors is an integer number (35327816100720).
Almost surely, 2540144022515311 is an apocalyptic number.
540144022515311 is a deficient number, since it is larger than the sum of its proper divisors (25101035096209).
540144022515311 is a wasteful number, since it uses less digits than its factorization.
540144022515311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2334526.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 540144022515311 its reverse (113515220441045), we get a palindrome (653659242956356).
The spelling of 540144022515311 in words is "five hundred forty trillion, one hundred forty-four billion, twenty-two million, five hundred fifteen thousand, three hundred eleven".
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