Base | Representation |
---|---|
bin | 11000100100001101000011… |
… | …00000110011010011010111 |
3 | 21002021022101110110021121112 |
4 | 30102012201200303103113 |
5 | 24040033002413143221 |
6 | 310520403053005235 |
7 | 14243565452516105 |
oct | 1422064140632327 |
9 | 232238343407545 |
10 | 54020513412311 |
11 | 16237a75566a76 |
12 | 608565478381b |
13 | 241b1603961b4 |
14 | d4a86d0b6c75 |
15 | 63a2e699d15b |
hex | 3121a18334d7 |
54020513412311 has 4 divisors (see below), whose sum is σ = 54020529285624. Its totient is φ = 54020497539000.
The previous prime is 54020513412289. The next prime is 54020513412391. The reversal of 54020513412311 is 11321431502045.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54020513412311 - 222 = 54020509218007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54020513412391) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524165 + ... + 10407486.
It is an arithmetic number, because the mean of its divisors is an integer number (13505132321406).
Almost surely, 254020513412311 is an apocalyptic number.
54020513412311 is a deficient number, since it is larger than the sum of its proper divisors (15873313).
54020513412311 is a wasteful number, since it uses less digits than its factorization.
54020513412311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15873312.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 54020513412311 its reverse (11321431502045), we get a palindrome (65341944914356).
The spelling of 54020513412311 in words is "fifty-four trillion, twenty billion, five hundred thirteen million, four hundred twelve thousand, three hundred eleven".
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