Base | Representation |
---|---|
bin | 11000100100001110100101… |
… | …10110101011101110001101 |
3 | 21002021101112011010212202111 |
4 | 30102013102312223232031 |
5 | 24040041201323411023 |
6 | 310521021144024021 |
7 | 14243625124050451 |
oct | 1422072266535615 |
9 | 232241464125674 |
10 | 54021341232013 |
11 | 1623835a879191 |
12 | 6085845a62011 |
13 | 241b262a3983c |
14 | d4a90b004661 |
15 | 63a3444bd00d |
hex | 3121d2dabb8d |
54021341232013 has 16 divisors (see below), whose sum is σ = 55744165016064. Its totient is φ = 52322501721600.
The previous prime is 54021341231983. The next prime is 54021341232029. The reversal of 54021341232013 is 31023214312045.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54021341232013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54021341230013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54678856 + ... + 55658062.
It is an arithmetic number, because the mean of its divisors is an integer number (3484010313504).
Almost surely, 254021341232013 is an apocalyptic number.
It is an amenable number.
54021341232013 is a deficient number, since it is larger than the sum of its proper divisors (1722823784051).
54021341232013 is a wasteful number, since it uses less digits than its factorization.
54021341232013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 991452.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 54021341232013 its reverse (31023214312045), we get a palindrome (85044555544058).
The spelling of 54021341232013 in words is "fifty-four trillion, twenty-one billion, three hundred forty-one million, two hundred thirty-two thousand, thirteen".
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