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54021341231983 is a prime number
BaseRepresentation
bin11000100100001110100101…
…10110101011101101101111
321002021101112011010212201101
430102013102312223231233
524040041201323410413
6310521021144023531
714243625124050406
oct1422072266535557
9232241464125641
1054021341231983
111623835a879164
126085845a61ba7
13241b262a39818
14d4a90b00463d
1563a3444bcedd
hex3121d2dabb6f

54021341231983 has 2 divisors, whose sum is σ = 54021341231984. Its totient is φ = 54021341231982.

The previous prime is 54021341231971. The next prime is 54021341232029. The reversal of 54021341231983 is 38913214312045.

It is an a-pointer prime, because the next prime (54021341232029) can be obtained adding 54021341231983 to its sum of digits (46).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 54021341231983 - 25 = 54021341231951 is a prime.

It is a super-2 number, since 2×540213412319832 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54021341231183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27010670615991 + 27010670615992.

It is an arithmetic number, because the mean of its divisors is an integer number (27010670615992).

Almost surely, 254021341231983 is an apocalyptic number.

54021341231983 is a deficient number, since it is larger than the sum of its proper divisors (1).

54021341231983 is an equidigital number, since it uses as much as digits as its factorization.

54021341231983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 622080, while the sum is 46.

The spelling of 54021341231983 in words is "fifty-four trillion, twenty-one billion, three hundred forty-one million, two hundred thirty-one thousand, nine hundred eighty-three".