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540213439 is a prime number
BaseRepresentation
bin100000001100110…
…000000010111111
31101122111200112011
4200030300002333
52101243312224
6125334352051
716246511203
oct4014600277
91348450464
10540213439
11257a33397
12130abb627
1387bc4b2c
1451a62b03
153265d394
hex203300bf

540213439 has 2 divisors, whose sum is σ = 540213440. Its totient is φ = 540213438.

The previous prime is 540213413. The next prime is 540213451. The reversal of 540213439 is 934312045.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 540213439 - 215 = 540180671 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 540213439.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (540213469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270106719 + 270106720.

It is an arithmetic number, because the mean of its divisors is an integer number (270106720).

Almost surely, 2540213439 is an apocalyptic number.

540213439 is a deficient number, since it is larger than the sum of its proper divisors (1).

540213439 is an equidigital number, since it uses as much as digits as its factorization.

540213439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

The square root of 540213439 is about 23242.4920996007. The cubic root of 540213439 is about 814.4325602129.

The spelling of 540213439 in words is "five hundred forty million, two hundred thirteen thousand, four hundred thirty-nine".