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5402200134013 = 9936754366139
BaseRepresentation
bin100111010011100110000…
…1110000101000101111101
3201010110000121121212212221
41032213030032011011331
51202002201213242023
615253423025125341
71065203361331054
oct116471416050575
921113017555787
105402200134013
1117a3073160131
12732b95a89851
1330256b47cc47
14149679c1d39b
15957cc36185d
hex4e9cc38517d

5402200134013 has 4 divisors (see below), whose sum is σ = 5402254599520. Its totient is φ = 5402145668508.

The previous prime is 5402200134011. The next prime is 5402200134053. The reversal of 5402200134013 is 3104310022045.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5402200134013 - 21 = 5402200134011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5402200134011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27083703 + ... + 27282436.

It is an arithmetic number, because the mean of its divisors is an integer number (1350563649880).

Almost surely, 25402200134013 is an apocalyptic number.

It is an amenable number.

5402200134013 is a deficient number, since it is larger than the sum of its proper divisors (54465507).

5402200134013 is an equidigital number, since it uses as much as digits as its factorization.

5402200134013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54465506.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 5402200134013 its reverse (3104310022045), we get a palindrome (8506510156058).

The spelling of 5402200134013 in words is "five trillion, four hundred two billion, two hundred million, one hundred thirty-four thousand, thirteen".

Divisors: 1 99367 54366139 5402200134013