Base | Representation |
---|---|
bin | 100111010011100110000… |
… | …1110000101000101111101 |
3 | 201010110000121121212212221 |
4 | 1032213030032011011331 |
5 | 1202002201213242023 |
6 | 15253423025125341 |
7 | 1065203361331054 |
oct | 116471416050575 |
9 | 21113017555787 |
10 | 5402200134013 |
11 | 17a3073160131 |
12 | 732b95a89851 |
13 | 30256b47cc47 |
14 | 149679c1d39b |
15 | 957cc36185d |
hex | 4e9cc38517d |
5402200134013 has 4 divisors (see below), whose sum is σ = 5402254599520. Its totient is φ = 5402145668508.
The previous prime is 5402200134011. The next prime is 5402200134053. The reversal of 5402200134013 is 3104310022045.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5402200134013 - 21 = 5402200134011 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5402200134011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27083703 + ... + 27282436.
It is an arithmetic number, because the mean of its divisors is an integer number (1350563649880).
Almost surely, 25402200134013 is an apocalyptic number.
It is an amenable number.
5402200134013 is a deficient number, since it is larger than the sum of its proper divisors (54465507).
5402200134013 is an equidigital number, since it uses as much as digits as its factorization.
5402200134013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54465506.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 5402200134013 its reverse (3104310022045), we get a palindrome (8506510156058).
The spelling of 5402200134013 in words is "five trillion, four hundred two billion, two hundred million, one hundred thirty-four thousand, thirteen".
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