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540231 = 3180077
BaseRepresentation
bin10000011111001000111
31000110001120
42003321013
5114241411
615325023
74410006
oct2037107
91013046
10540231
1133997a
12220773
1315bb83
14100c3d
15aa106
hex83e47

540231 has 4 divisors (see below), whose sum is σ = 720312. Its totient is φ = 360152.

The previous prime is 540217. The next prime is 540233. The reversal of 540231 is 132045.

540231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 540231 - 26 = 540167 is a prime.

It is a super-2 number, since 2×5402312 = 583699066722, which contains 22 as substring.

It is a D-number.

It is a self number, because there is not a number n which added to its sum of digits gives 540231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (540233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90036 + ... + 90041.

It is an arithmetic number, because the mean of its divisors is an integer number (180078).

2540231 is an apocalyptic number.

540231 is a deficient number, since it is larger than the sum of its proper divisors (180081).

540231 is a wasteful number, since it uses less digits than its factorization.

540231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 180080.

The product of its (nonzero) digits is 120, while the sum is 15.

The square root of 540231 is about 735.0040816213. The cubic root of 540231 is about 81.4441385179. Note that the first 3 decimals are identical.

Adding to 540231 its reverse (132045), we get a palindrome (672276).

The spelling of 540231 in words is "five hundred forty thousand, two hundred thirty-one".

Divisors: 1 3 180077 540231