Base | Representation |
---|---|
bin | 110010010100000101… |
… | …110010010101101111 |
3 | 12011110000222021222111 |
4 | 302110011302111233 |
5 | 1341120140334211 |
6 | 40452433024451 |
7 | 3621524501404 |
oct | 622405622557 |
9 | 164400867874 |
10 | 54024152431 |
11 | 20a03253367 |
12 | a5786b5127 |
13 | 512c699902 |
14 | 2886d702ab |
15 | 1612cdb421 |
hex | c9417256f |
54024152431 has 2 divisors, whose sum is σ = 54024152432. Its totient is φ = 54024152430.
The previous prime is 54024152419. The next prime is 54024152471. The reversal of 54024152431 is 13425142045.
54024152431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54024152431 is a prime.
It is a super-2 number, since 2×540241524312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54024152393 and 54024152402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54024152401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27012076215 + 27012076216.
It is an arithmetic number, because the mean of its divisors is an integer number (27012076216).
Almost surely, 254024152431 is an apocalyptic number.
54024152431 is a deficient number, since it is larger than the sum of its proper divisors (1).
54024152431 is an equidigital number, since it uses as much as digits as its factorization.
54024152431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 54024152431 its reverse (13425142045), we get a palindrome (67449294476).
The spelling of 54024152431 in words is "fifty-four billion, twenty-four million, one hundred fifty-two thousand, four hundred thirty-one".
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