Base | Representation |
---|---|
bin | 1111101110010010110… |
… | …10101111111010011011 |
3 | 1220122110221221220100211 |
4 | 13313021122233322123 |
5 | 32322413014110121 |
6 | 1052104255311551 |
7 | 54013621313215 |
oct | 7671132577233 |
9 | 1818427856324 |
10 | 540250144411 |
11 | 19913413875a |
12 | 8885481b5b7 |
13 | 3bc39c93683 |
14 | 1c210b075b5 |
15 | e0be57bce1 |
hex | 7dc96afe9b |
540250144411 has 2 divisors, whose sum is σ = 540250144412. Its totient is φ = 540250144410.
The previous prime is 540250144409. The next prime is 540250144457. The reversal of 540250144411 is 114441052045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 540250144411 - 21 = 540250144409 is a prime.
It is a super-2 number, since 2×5402501444112 (a number of 24 digits) contains 22 as substring.
Together with 540250144409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (540250144481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270125072205 + 270125072206.
It is an arithmetic number, because the mean of its divisors is an integer number (270125072206).
Almost surely, 2540250144411 is an apocalyptic number.
540250144411 is a deficient number, since it is larger than the sum of its proper divisors (1).
540250144411 is an equidigital number, since it uses as much as digits as its factorization.
540250144411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 540250144411 its reverse (114441052045), we get a palindrome (654691196456).
The spelling of 540250144411 in words is "five hundred forty billion, two hundred fifty million, one hundred forty-four thousand, four hundred eleven".
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