Base | Representation |
---|---|
bin | 11000100100011110110100… |
… | …00100100110000101001111 |
3 | 21002022020000020110122111121 |
4 | 30102033122010212011033 |
5 | 24040212021334112111 |
6 | 310525021403301411 |
7 | 14244354030366220 |
oct | 1422173204460517 |
9 | 232266006418447 |
10 | 54030052254031 |
11 | 1624101aa33a37 |
12 | 608747721a867 |
13 | 241c02067ab39 |
14 | d4b0d5cb5247 |
15 | 63a6a4116871 |
hex | 3123da12614f |
54030052254031 has 192 divisors, whose sum is σ = 70140069457920. Its totient is φ = 40677837742080.
The previous prime is 54030052253993. The next prime is 54030052254037. The reversal of 54030052254031 is 13045225003045.
It is not a de Polignac number, because 54030052254031 - 211 = 54030052251983 is a prime.
It is a super-2 number, since 2×540300522540312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54030052254037) by changing a digit.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 52304019091 + ... + 52304020123.
It is an arithmetic number, because the mean of its divisors is an integer number (365312861760).
Almost surely, 254030052254031 is an apocalyptic number.
54030052254031 is a deficient number, since it is larger than the sum of its proper divisors (16110017203889).
54030052254031 is a wasteful number, since it uses less digits than its factorization.
54030052254031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1446 (or 1423 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 34.
Adding to 54030052254031 its reverse (13045225003045), we get a palindrome (67075277257076).
The spelling of 54030052254031 in words is "fifty-four trillion, thirty billion, fifty-two million, two hundred fifty-four thousand, thirty-one".
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