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540303413005002 = 23611476238833347
BaseRepresentation
bin111101011011001110011000…
…1000000001100101011001010
32121212001111112211121022011210
41322312130301000030223022
51031304312342212130002
65153043543351433550
7221543430154145013
oct17266346100145312
92555044484538153
10540303413005002
11147180432a62329
12507225079858b6
131a263515bb742a
14975cb7906c00a
15426e7e974e96c
hex1eb673100caca

540303413005002 has 16 divisors (see below), whose sum is σ = 1098321692010912. Its totient is φ = 177148660001520.

The previous prime is 540303413004967. The next prime is 540303413005061. The reversal of 540303413005002 is 200500314303045.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 738119416308 + ... + 738119417039.

It is an arithmetic number, because the mean of its divisors is an integer number (68645105750682).

Almost surely, 2540303413005002 is an apocalyptic number.

540303413005002 is an abundant number, since it is smaller than the sum of its proper divisors (558018279005910).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

540303413005002 is a wasteful number, since it uses less digits than its factorization.

540303413005002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1476238833413.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 540303413005002 its reverse (200500314303045), we get a palindrome (740803727308047).

The spelling of 540303413005002 in words is "five hundred forty trillion, three hundred three billion, four hundred thirteen million, five thousand, two".

Divisors: 1 2 3 6 61 122 183 366 1476238833347 2952477666694 4428716500041 8857433000082 90050568834167 180101137668334 270151706502501 540303413005002