Base | Representation |
---|---|
bin | 111101011011100110100100… |
… | …0010011000111110110100111 |
3 | 2121212020110120221220012211102 |
4 | 1322313031020103013312213 |
5 | 1031311140220410341021 |
6 | 5153123452353230315 |
7 | 221550246066506612 |
oct | 17267151023076647 |
9 | 2555213527805742 |
10 | 540355343449511 |
11 | 1471a0461384967 |
12 | 5073059b26239b |
13 | 1a2683a088a0c5 |
14 | 97614a3d0d179 |
15 | 4270d3881800b |
hex | 1eb73484c7da7 |
540355343449511 has 2 divisors, whose sum is σ = 540355343449512. Its totient is φ = 540355343449510.
The previous prime is 540355343449487. The next prime is 540355343449531. The reversal of 540355343449511 is 115944343553045.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 540355343449511 - 226 = 540355276340647 is a prime.
It is a super-2 number, since 2×5403553434495112 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540355343449531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270177671724755 + 270177671724756.
It is an arithmetic number, because the mean of its divisors is an integer number (270177671724756).
Almost surely, 2540355343449511 is an apocalyptic number.
540355343449511 is a deficient number, since it is larger than the sum of its proper divisors (1).
540355343449511 is an equidigital number, since it uses as much as digits as its factorization.
540355343449511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880000, while the sum is 56.
The spelling of 540355343449511 in words is "five hundred forty trillion, three hundred fifty-five billion, three hundred forty-three million, four hundred forty-nine thousand, five hundred eleven".
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