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5404110456131 is a prime number
BaseRepresentation
bin100111010100011111000…
…0101011000010101000011
3201010121221202020022011222
41032220332011120111003
51202020104234044011
615254340350025255
71065301615651232
oct116507605302503
921117852208158
105404110456131
1117a3963516442
127334297a822b
133027b4188b6a
141497bb812b19
159588ee0cddb
hex4ea3e158543

5404110456131 has 2 divisors, whose sum is σ = 5404110456132. Its totient is φ = 5404110456130.

The previous prime is 5404110456119. The next prime is 5404110456133. The reversal of 5404110456131 is 1316540114045.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5404110456131 - 230 = 5403036714307 is a prime.

It is a super-2 number, since 2×54041104561312 (a number of 26 digits) contains 22 as substring.

Together with 5404110456133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5404110456091 and 5404110456100.

It is not a weakly prime, because it can be changed into another prime (5404110456133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2702055228065 + 2702055228066.

It is an arithmetic number, because the mean of its divisors is an integer number (2702055228066).

Almost surely, 25404110456131 is an apocalyptic number.

5404110456131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5404110456131 is an equidigital number, since it uses as much as digits as its factorization.

5404110456131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 35.

The spelling of 5404110456131 in words is "five trillion, four hundred four billion, one hundred ten million, four hundred fifty-six thousand, one hundred thirty-one".