Base | Representation |
---|---|
bin | 100111010100011111000… |
… | …0101011000010101000011 |
3 | 201010121221202020022011222 |
4 | 1032220332011120111003 |
5 | 1202020104234044011 |
6 | 15254340350025255 |
7 | 1065301615651232 |
oct | 116507605302503 |
9 | 21117852208158 |
10 | 5404110456131 |
11 | 17a3963516442 |
12 | 7334297a822b |
13 | 3027b4188b6a |
14 | 1497bb812b19 |
15 | 9588ee0cddb |
hex | 4ea3e158543 |
5404110456131 has 2 divisors, whose sum is σ = 5404110456132. Its totient is φ = 5404110456130.
The previous prime is 5404110456119. The next prime is 5404110456133. The reversal of 5404110456131 is 1316540114045.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5404110456131 - 230 = 5403036714307 is a prime.
It is a super-2 number, since 2×54041104561312 (a number of 26 digits) contains 22 as substring.
Together with 5404110456133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5404110456091 and 5404110456100.
It is not a weakly prime, because it can be changed into another prime (5404110456133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2702055228065 + 2702055228066.
It is an arithmetic number, because the mean of its divisors is an integer number (2702055228066).
Almost surely, 25404110456131 is an apocalyptic number.
5404110456131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5404110456131 is an equidigital number, since it uses as much as digits as its factorization.
5404110456131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 35.
The spelling of 5404110456131 in words is "five trillion, four hundred four billion, one hundred ten million, four hundred fifty-six thousand, one hundred thirty-one".
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