Base | Representation |
---|---|
bin | 110010010101000111… |
… | …010111010101100111 |
3 | 12011111020022200110122 |
4 | 302111013113111213 |
5 | 1341134040441320 |
6 | 40454245312155 |
7 | 3622123560560 |
oct | 622507272547 |
9 | 164436280418 |
10 | 54041343335 |
11 | 20a11a25121 |
12 | a58240565b |
13 | 5133108545 |
14 | 2889367167 |
15 | 1614584d25 |
hex | c951d7567 |
54041343335 has 16 divisors (see below), whose sum is σ = 74127134016. Its totient is φ = 37050275328.
The previous prime is 54041343287. The next prime is 54041343353. The reversal of 54041343335 is 53334314045.
It is a cyclic number.
It is not a de Polignac number, because 54041343335 - 212 = 54041339239 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54041343295 and 54041343304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63647 + ... + 334863.
It is an arithmetic number, because the mean of its divisors is an integer number (4632945876).
Almost surely, 254041343335 is an apocalyptic number.
54041343335 is a deficient number, since it is larger than the sum of its proper divisors (20085790681).
54041343335 is a wasteful number, since it uses less digits than its factorization.
54041343335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 276922.
The product of its (nonzero) digits is 129600, while the sum is 35.
The spelling of 54041343335 in words is "fifty-four billion, forty-one million, three hundred forty-three thousand, three hundred thirty-five".
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