Base | Representation |
---|---|
bin | 11000100100110101001010… |
… | …11100011100100000010101 |
3 | 21002100100222200021110202111 |
4 | 30102122211130130200111 |
5 | 24040411111334400301 |
6 | 310534324343111021 |
7 | 14245260324363136 |
oct | 1422324534344025 |
9 | 232310880243674 |
10 | 54042054215701 |
11 | 16246119805422 |
12 | 6089866742471 |
13 | 24201b404b4c6 |
14 | d4b913c83c8d |
15 | 63ab57b23551 |
hex | 3126a571c815 |
54042054215701 has 2 divisors, whose sum is σ = 54042054215702. Its totient is φ = 54042054215700.
The previous prime is 54042054215641. The next prime is 54042054215707. The reversal of 54042054215701 is 10751245024045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52315855020900 + 1726199194801 = 7232970^2 + 1313849^2 .
It is a cyclic number.
It is not a de Polignac number, because 54042054215701 - 29 = 54042054215189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54042054215707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27021027107850 + 27021027107851.
It is an arithmetic number, because the mean of its divisors is an integer number (27021027107851).
Almost surely, 254042054215701 is an apocalyptic number.
It is an amenable number.
54042054215701 is a deficient number, since it is larger than the sum of its proper divisors (1).
54042054215701 is an equidigital number, since it uses as much as digits as its factorization.
54042054215701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224000, while the sum is 40.
Adding to 54042054215701 its reverse (10751245024045), we get a palindrome (64793299239746).
The spelling of 54042054215701 in words is "fifty-four trillion, forty-two billion, fifty-four million, two hundred fifteen thousand, seven hundred one".
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