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54051252010501 is a prime number
BaseRepresentation
bin11000100101000110010011…
…01011001111111000000101
321002101020201200112212020011
430102203021223033320011
524041033431003314001
6310542445151510221
714246034261345334
oct1422431153177005
9232336650485204
1054051252010501
111624a009712829
12608b5b2b28371
13242101b793135
14d4c147665d1b
1563aee5370d51
hex3128c9acfe05

54051252010501 has 2 divisors, whose sum is σ = 54051252010502. Its totient is φ = 54051252010500.

The previous prime is 54051252010423. The next prime is 54051252010517. The reversal of 54051252010501 is 10501025215045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52431356902500 + 1619895108001 = 7240950^2 + 1272751^2 .

It is a cyclic number.

It is not a de Polignac number, because 54051252010501 - 239 = 53501496196613 is a prime.

It is a super-2 number, since 2×540512520105012 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54051252010601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27025626005250 + 27025626005251.

It is an arithmetic number, because the mean of its divisors is an integer number (27025626005251).

Almost surely, 254051252010501 is an apocalyptic number.

It is an amenable number.

54051252010501 is a deficient number, since it is larger than the sum of its proper divisors (1).

54051252010501 is an equidigital number, since it uses as much as digits as its factorization.

54051252010501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10000, while the sum is 31.

Adding to 54051252010501 its reverse (10501025215045), we get a palindrome (64552277225546).

The spelling of 54051252010501 in words is "fifty-four trillion, fifty-one billion, two hundred fifty-two million, ten thousand, five hundred one".