Base | Representation |
---|---|
bin | 11000100101010110101101… |
… | …01011001111011101000101 |
3 | 21002102002110112102111001121 |
4 | 30102223112223033131011 |
5 | 24041210000333002143 |
6 | 310550503154353541 |
7 | 14246465453413465 |
oct | 1422532653173505 |
9 | 232362415374047 |
10 | 54060060047173 |
11 | 16252819610084 |
12 | 609125088b8b1 |
13 | 2421ac354115b |
14 | d4c74138bba5 |
15 | 63b35d77e7ed |
hex | 312ad6acf745 |
54060060047173 has 2 divisors, whose sum is σ = 54060060047174. Its totient is φ = 54060060047172.
The previous prime is 54060060047131. The next prime is 54060060047207. The reversal of 54060060047173 is 37174006006045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44938494289924 + 9121565757249 = 6703618^2 + 3020193^2 .
It is a cyclic number.
It is not a de Polignac number, because 54060060047173 - 233 = 54051470112581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54060060047113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27030030023586 + 27030030023587.
It is an arithmetic number, because the mean of its divisors is an integer number (27030030023587).
Almost surely, 254060060047173 is an apocalyptic number.
It is an amenable number.
54060060047173 is a deficient number, since it is larger than the sum of its proper divisors (1).
54060060047173 is an equidigital number, since it uses as much as digits as its factorization.
54060060047173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 423360, while the sum is 43.
The spelling of 54060060047173 in words is "fifty-four trillion, sixty billion, sixty million, forty-seven thousand, one hundred seventy-three".
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