Base | Representation |
---|---|
bin | 11000100101010110111010… |
… | …10001100000110110000101 |
3 | 21002102002202020201102102110 |
4 | 30102223131101200312011 |
5 | 24041210212202240143 |
6 | 310550522151131233 |
7 | 14246501266334400 |
oct | 1422533521406605 |
9 | 232362666642373 |
10 | 54060170743173 |
11 | 16252876047681 |
12 | 6091281973b19 |
13 | 2421b1045b24a |
14 | d4c751d64d37 |
15 | 63b368348533 |
hex | 312add460d85 |
54060170743173 has 24 divisors (see below), whose sum is σ = 83850161666880. Its totient is φ = 30890887453440.
The previous prime is 54060170743151. The next prime is 54060170743181. The reversal of 54060170743173 is 37134707106045.
It is not a de Polignac number, because 54060170743173 - 212 = 54060170739077 is a prime.
It is a super-2 number, since 2×540601707431732 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54060170743573) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3378453 + ... + 10933173.
It is an arithmetic number, because the mean of its divisors is an integer number (3493756736120).
Almost surely, 254060170743173 is an apocalyptic number.
It is an amenable number.
54060170743173 is a deficient number, since it is larger than the sum of its proper divisors (29789990923707).
54060170743173 is a wasteful number, since it uses less digits than its factorization.
54060170743173 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7603417 (or 7603410 counting only the distinct ones).
The product of its (nonzero) digits is 1481760, while the sum is 48.
The spelling of 54060170743173 in words is "fifty-four trillion, sixty billion, one hundred seventy million, seven hundred forty-three thousand, one hundred seventy-three".
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