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540747325198121 is a prime number
BaseRepresentation
bin111101011110011101000110…
…0001110110100111100101001
32121220121221100211201012201112
41322330322030032310330221
51031334101010222314441
65154023520342400105
7221620463546423456
oct17274721416647451
92556557324635645
10540747325198121
1114733171a903318
1250794555130035
131a29633bc64aa2
14977644b21682d
15427b12b30d4eb
hex1ebce8c3b4f29

540747325198121 has 2 divisors, whose sum is σ = 540747325198122. Its totient is φ = 540747325198120.

The previous prime is 540747325198061. The next prime is 540747325198141. The reversal of 540747325198121 is 121891523747045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 497126108505625 + 43621216692496 = 22296325^2 + 6604636^2 .

It is a cyclic number.

It is not a de Polignac number, because 540747325198121 - 218 = 540747324935977 is a prime.

It is not a weakly prime, because it can be changed into another prime (540747325198141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270373662599060 + 270373662599061.

It is an arithmetic number, because the mean of its divisors is an integer number (270373662599061).

Almost surely, 2540747325198121 is an apocalyptic number.

It is an amenable number.

540747325198121 is a deficient number, since it is larger than the sum of its proper divisors (1).

540747325198121 is an equidigital number, since it uses as much as digits as its factorization.

540747325198121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16934400, while the sum is 59.

The spelling of 540747325198121 in words is "five hundred forty trillion, seven hundred forty-seven billion, three hundred twenty-five million, one hundred ninety-eight thousand, one hundred twenty-one".