Search a number
-
+
540747325198141 is a prime number
BaseRepresentation
bin111101011110011101000110…
…0001110110100111100111101
32121220121221100211201012202021
41322330322030032310330331
51031334101010222320031
65154023520342400141
7221620463546423515
oct17274721416647475
92556557324635667
10540747325198141
1114733171a903336
1250794555130051
131a29633bc64ab9
14977644b216845
15427b12b30d511
hex1ebce8c3b4f3d

540747325198141 has 2 divisors, whose sum is σ = 540747325198142. Its totient is φ = 540747325198140.

The previous prime is 540747325198121. The next prime is 540747325198189. The reversal of 540747325198141 is 141891523747045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 530178025104025 + 10569300094116 = 23025595^2 + 3251046^2 .

It is a cyclic number.

It is not a de Polignac number, because 540747325198141 - 215 = 540747325165373 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 540747325198141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (540747325198121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270373662599070 + 270373662599071.

It is an arithmetic number, because the mean of its divisors is an integer number (270373662599071).

Almost surely, 2540747325198141 is an apocalyptic number.

It is an amenable number.

540747325198141 is a deficient number, since it is larger than the sum of its proper divisors (1).

540747325198141 is an equidigital number, since it uses as much as digits as its factorization.

540747325198141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33868800, while the sum is 61.

The spelling of 540747325198141 in words is "five hundred forty trillion, seven hundred forty-seven billion, three hundred twenty-five million, one hundred ninety-eight thousand, one hundred forty-one".