Base | Representation |
---|---|
bin | 11000100101110111010011… |
… | …11101011011001100011101 |
3 | 21002110202122101011111000121 |
4 | 30102323221331123030131 |
5 | 24042001322220401031 |
6 | 311002520101154541 |
7 | 14250655302034030 |
oct | 1422735175331435 |
9 | 232422571144017 |
10 | 54077563450141 |
11 | 1625a19084a870 |
12 | 60947166bba51 |
13 | 242365290b52a |
14 | d4d521c6b017 |
15 | 63ba35243011 |
hex | 312ee9f5b31d |
54077563450141 has 32 divisors (see below), whose sum is σ = 67826248335360. Its totient is φ = 41885654827200.
The previous prime is 54077563450109. The next prime is 54077563450147. The reversal of 54077563450141 is 14105436577045.
It is a cyclic number.
It is not a de Polignac number, because 54077563450141 - 25 = 54077563450109 is a prime.
It is a super-3 number, since 3×540775634501413 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54077563450147) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17815395 + ... + 20628703.
It is an arithmetic number, because the mean of its divisors is an integer number (2119570260480).
Almost surely, 254077563450141 is an apocalyptic number.
It is an amenable number.
54077563450141 is a deficient number, since it is larger than the sum of its proper divisors (13748684885219).
54077563450141 is a wasteful number, since it uses less digits than its factorization.
54077563450141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2814825.
The product of its (nonzero) digits is 7056000, while the sum is 52.
The spelling of 54077563450141 in words is "fifty-four trillion, seventy-seven billion, five hundred sixty-three million, four hundred fifty thousand, one hundred forty-one".
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