Base | Representation |
---|---|
bin | 100111010111001001110… |
… | …1001100001010111000011 |
3 | 201011011202010012002222200 |
4 | 1032232103221201113003 |
5 | 1202113323241222323 |
6 | 15301125134404243 |
7 | 1065563621310345 |
oct | 116562351412703 |
9 | 21134663162880 |
10 | 5409840960963 |
11 | 17a633420854a |
12 | 734568960683 |
13 | 3031b847781a |
14 | 149ba290d295 |
15 | 95ac8060443 |
hex | 4eb93a615c3 |
5409840960963 has 12 divisors (see below), whose sum is σ = 7817228335800. Its totient is φ = 3605169741696.
The previous prime is 5409840960961. The next prime is 5409840960983. The reversal of 5409840960963 is 3690690489045.
5409840960963 is a `hidden beast` number, since 5 + 409 + 84 + 0 + 9 + 60 + 96 + 3 = 666.
It is not a de Polignac number, because 5409840960963 - 21 = 5409840960961 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5409840960963.
It is not an unprimeable number, because it can be changed into a prime (5409840960961) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 115883613 + ... + 115930286.
It is an arithmetic number, because the mean of its divisors is an integer number (651435694650).
Almost surely, 25409840960963 is an apocalyptic number.
5409840960963 is a deficient number, since it is larger than the sum of its proper divisors (2407387374837).
5409840960963 is a wasteful number, since it uses less digits than its factorization.
5409840960963 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231816498 (or 231816495 counting only the distinct ones).
The product of its (nonzero) digits is 50388480, while the sum is 63.
The spelling of 5409840960963 in words is "five trillion, four hundred nine billion, eight hundred forty million, nine hundred sixty thousand, nine hundred sixty-three".
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