Base | Representation |
---|---|
bin | 111101100000010011111100… |
… | …0001110111011001100000001 |
3 | 2121221112100010012211022110021 |
4 | 1323000213320032323030001 |
5 | 1031402241200244432343 |
6 | 5154341045210333441 |
7 | 221645100165426103 |
oct | 17300477016731401 |
9 | 2557470105738407 |
10 | 541002540233473 |
11 | 14741a98606683a |
12 | 50815b0012a281 |
13 | 1a2b44225a22c6 |
14 | 978493c4a3573 |
15 | 4282ab6da80ed |
hex | 1ec09f83bb301 |
541002540233473 has 2 divisors, whose sum is σ = 541002540233474. Its totient is φ = 541002540233472.
The previous prime is 541002540233431. The next prime is 541002540233489. The reversal of 541002540233473 is 374332045200145.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 520890607088784 + 20111933144689 = 22823028^2 + 4484633^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-541002540233473 is a prime.
It is not a weakly prime, because it can be changed into another prime (541002540233173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270501270116736 + 270501270116737.
It is an arithmetic number, because the mean of its divisors is an integer number (270501270116737).
Almost surely, 2541002540233473 is an apocalyptic number.
It is an amenable number.
541002540233473 is a deficient number, since it is larger than the sum of its proper divisors (1).
541002540233473 is an equidigital number, since it uses as much as digits as its factorization.
541002540233473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1209600, while the sum is 43.
The spelling of 541002540233473 in words is "five hundred forty-one trillion, two billion, five hundred forty million, two hundred thirty-three thousand, four hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •