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541002540233431 is a prime number
BaseRepresentation
bin111101100000010011111100…
…0001110111011001011010111
32121221112100010012211022101201
41323000213320032323023113
51031402241200244432211
65154341045210333331
7221645100165426013
oct17300477016731327
92557470105738351
10541002540233431
1114741a986066801
1250815b0012a247
131a2b44225a2293
14978493c4a3543
154282ab6da80c1
hex1ec09f83bb2d7

541002540233431 has 2 divisors, whose sum is σ = 541002540233432. Its totient is φ = 541002540233430.

The previous prime is 541002540233417. The next prime is 541002540233473. The reversal of 541002540233431 is 134332045200145.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 541002540233431 - 211 = 541002540231383 is a prime.

It is a super-3 number, since 3×5410025402334313 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (541002540233411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270501270116715 + 270501270116716.

It is an arithmetic number, because the mean of its divisors is an integer number (270501270116716).

Almost surely, 2541002540233431 is an apocalyptic number.

541002540233431 is a deficient number, since it is larger than the sum of its proper divisors (1).

541002540233431 is an equidigital number, since it uses as much as digits as its factorization.

541002540233431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 541002540233431 its reverse (134332045200145), we get a palindrome (675334585433576).

The spelling of 541002540233431 in words is "five hundred forty-one trillion, two billion, five hundred forty million, two hundred thirty-three thousand, four hundred thirty-one".