Base | Representation |
---|---|
bin | 111101100000010011111100… |
… | …0001110111011001011010111 |
3 | 2121221112100010012211022101201 |
4 | 1323000213320032323023113 |
5 | 1031402241200244432211 |
6 | 5154341045210333331 |
7 | 221645100165426013 |
oct | 17300477016731327 |
9 | 2557470105738351 |
10 | 541002540233431 |
11 | 14741a986066801 |
12 | 50815b0012a247 |
13 | 1a2b44225a2293 |
14 | 978493c4a3543 |
15 | 4282ab6da80c1 |
hex | 1ec09f83bb2d7 |
541002540233431 has 2 divisors, whose sum is σ = 541002540233432. Its totient is φ = 541002540233430.
The previous prime is 541002540233417. The next prime is 541002540233473. The reversal of 541002540233431 is 134332045200145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 541002540233431 - 211 = 541002540231383 is a prime.
It is a super-3 number, since 3×5410025402334313 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (541002540233411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270501270116715 + 270501270116716.
It is an arithmetic number, because the mean of its divisors is an integer number (270501270116716).
Almost surely, 2541002540233431 is an apocalyptic number.
541002540233431 is a deficient number, since it is larger than the sum of its proper divisors (1).
541002540233431 is an equidigital number, since it uses as much as digits as its factorization.
541002540233431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 541002540233431 its reverse (134332045200145), we get a palindrome (675334585433576).
The spelling of 541002540233431 in words is "five hundred forty-one trillion, two billion, five hundred forty million, two hundred thirty-three thousand, four hundred thirty-one".
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