Base | Representation |
---|---|
bin | 100111010111001111111… |
… | …0001011001111111110111 |
3 | 201011012021021220120112112 |
4 | 1032232133301121333313 |
5 | 1202114232323321201 |
6 | 15301201242041235 |
7 | 1065601641160514 |
oct | 116563761317767 |
9 | 21135237816475 |
10 | 5410044354551 |
11 | 17a6428aa9121 |
12 | 734604aa921b |
13 | 30321b64c665 |
14 | 149bc193630b |
15 | 95adad3a0bb |
hex | 4eb9fc59ff7 |
5410044354551 has 2 divisors, whose sum is σ = 5410044354552. Its totient is φ = 5410044354550.
The previous prime is 5410044354467. The next prime is 5410044354601. The reversal of 5410044354551 is 1554534400145.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5410044354551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5410044354499 and 5410044354508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5410044354251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705022177275 + 2705022177276.
It is an arithmetic number, because the mean of its divisors is an integer number (2705022177276).
Almost surely, 25410044354551 is an apocalyptic number.
5410044354551 is a deficient number, since it is larger than the sum of its proper divisors (1).
5410044354551 is an equidigital number, since it uses as much as digits as its factorization.
5410044354551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480000, while the sum is 41.
Adding to 5410044354551 its reverse (1554534400145), we get a palindrome (6964578754696).
The spelling of 5410044354551 in words is "five trillion, four hundred ten billion, forty-four million, three hundred fifty-four thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.104 sec. • engine limits •