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54103144603 = 333116242313
BaseRepresentation
bin110010011000110011…
…000111100010011011
312011122112121111212111
4302120303013202123
51341300401111403
640504334053151
73623504066314
oct623063074233
9164575544774
1054103144603
1120a438a6352
12a59b04a1b7
135142b66341
14289365360b
151619be156d
hexc98cc789b

54103144603 has 4 divisors (see below), whose sum is σ = 54119390248. Its totient is φ = 54086898960.

The previous prime is 54103144583. The next prime is 54103144619. The reversal of 54103144603 is 30644130145.

It is a happy number.

54103144603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54103144603 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54103147603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8117826 + ... + 8124487.

It is an arithmetic number, because the mean of its divisors is an integer number (13529847562).

Almost surely, 254103144603 is an apocalyptic number.

54103144603 is a deficient number, since it is larger than the sum of its proper divisors (16245645).

54103144603 is a wasteful number, since it uses less digits than its factorization.

54103144603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16245644.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 54103144603 its reverse (30644130145), we get a palindrome (84747274748).

The spelling of 54103144603 in words is "fifty-four billion, one hundred three million, one hundred forty-four thousand, six hundred three".

Divisors: 1 3331 16242313 54103144603