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541040332333 is a prime number
BaseRepresentation
bin1111101111110001000…
…01000100111000101101
31220201112000211121102011
413313320201010320231
532331022311113313
61052314524001221
754042324642124
oct7677041047055
91821460747364
10541040332333
111994aa187626
1288a35390211
133c0348bc3a7
141c287a3aabb
15e118b1693d
hex7df8844e2d

541040332333 has 2 divisors, whose sum is σ = 541040332334. Its totient is φ = 541040332332.

The previous prime is 541040332309. The next prime is 541040332387. The reversal of 541040332333 is 333233040145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 527768831529 + 13271500804 = 726477^2 + 115202^2 .

It is a cyclic number.

It is not a de Polignac number, because 541040332333 - 225 = 541006777901 is a prime.

It is a super-2 number, since 2×5410403323332 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 541040332295 and 541040332304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (541040332303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270520166166 + 270520166167.

It is an arithmetic number, because the mean of its divisors is an integer number (270520166167).

Almost surely, 2541040332333 is an apocalyptic number.

It is an amenable number.

541040332333 is a deficient number, since it is larger than the sum of its proper divisors (1).

541040332333 is an equidigital number, since it uses as much as digits as its factorization.

541040332333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 31.

Adding to 541040332333 its reverse (333233040145), we get a palindrome (874273372478).

The spelling of 541040332333 in words is "five hundred forty-one billion, forty million, three hundred thirty-two thousand, three hundred thirty-three".