Base | Representation |
---|---|
bin | 100111010111011010110… |
… | …1010010110100110110001 |
3 | 201011020012212221210121211 |
4 | 1032232311222112212301 |
5 | 1202121010332320101 |
6 | 15301301521320121 |
7 | 1065614020561006 |
oct | 116566552264661 |
9 | 21136185853554 |
10 | 5410411604401 |
11 | 17a65a73353a1 |
12 | 7346a7a96041 |
13 | 30327976526b |
14 | 149c186138ad |
15 | 95b0d1cec51 |
hex | 4ebb5a969b1 |
5410411604401 has 2 divisors, whose sum is σ = 5410411604402. Its totient is φ = 5410411604400.
The previous prime is 5410411604251. The next prime is 5410411604419. The reversal of 5410411604401 is 1044061140145.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4417899534400 + 992512070001 = 2101880^2 + 996249^2 .
It is a cyclic number.
It is not a de Polignac number, because 5410411604401 - 29 = 5410411603889 is a prime.
It is not a weakly prime, because it can be changed into another prime (5410411604491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705205802200 + 2705205802201.
It is an arithmetic number, because the mean of its divisors is an integer number (2705205802201).
Almost surely, 25410411604401 is an apocalyptic number.
It is an amenable number.
5410411604401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5410411604401 is an equidigital number, since it uses as much as digits as its factorization.
5410411604401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 5410411604401 its reverse (1044061140145), we get a palindrome (6454472744546).
The spelling of 5410411604401 in words is "five trillion, four hundred ten billion, four hundred eleven million, six hundred four thousand, four hundred one".
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