Search a number
-
+
54105443401 = 4110312812087
BaseRepresentation
bin110010011000111011…
…111000110001001001
312011122200221022020011
4302120323320301021
51341301443142101
640504455231521
73623532452332
oct623073706111
9164580838204
1054105443401
1120a45126489
12a59b9785a1
13514348c789
142893a91289
151619ee7751
hexc98ef8c49

54105443401 has 8 divisors (see below), whose sum is σ = 55963200384. Its totient is φ = 52273310880.

The previous prime is 54105443339. The next prime is 54105443411. The reversal of 54105443401 is 10434450145.

54105443401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 54105443401 - 215 = 54105410633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54105443411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6401821 + ... + 6410266.

It is an arithmetic number, because the mean of its divisors is an integer number (6995400048).

Almost surely, 254105443401 is an apocalyptic number.

It is an amenable number.

54105443401 is a deficient number, since it is larger than the sum of its proper divisors (1857756983).

54105443401 is a wasteful number, since it uses less digits than its factorization.

54105443401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12812231.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 54105443401 its reverse (10434450145), we get a palindrome (64539893546).

The spelling of 54105443401 in words is "fifty-four billion, one hundred five million, four hundred forty-three thousand, four hundred one".

Divisors: 1 41 103 4223 12812087 525295567 1319644961 54105443401