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54106626313555 = 510821325262711
BaseRepresentation
bin11000100110101101011100…
…01111011100110101010011
321002120112122211001220200021
430103112232033130311103
524042440332314013210
6311024124015204311
714253034432223164
oct1423265617346523
9232515584056607
1054106626313555
1116270544aa7252
12609a287816697
132426304aa682a
14d50abba4d76b
1563c686956bda
hex3135ae3dcd53

54106626313555 has 4 divisors (see below), whose sum is σ = 64927951576272. Its totient is φ = 43285301050840.

The previous prime is 54106626313549. The next prime is 54106626313561. The reversal of 54106626313555 is 55531362660145.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (54106626313549) and next prime (54106626313561).

It is not a de Polignac number, because 54106626313555 - 213 = 54106626305363 is a prime.

It is a super-2 number, since 2×541066263135552 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5410662631351 + ... + 5410662631360.

It is an arithmetic number, because the mean of its divisors is an integer number (16231987894068).

Almost surely, 254106626313555 is an apocalyptic number.

54106626313555 is a deficient number, since it is larger than the sum of its proper divisors (10821325262717).

54106626313555 is a wasteful number, since it uses less digits than its factorization.

54106626313555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10821325262716.

The product of its (nonzero) digits is 9720000, while the sum is 52.

The spelling of 54106626313555 in words is "fifty-four trillion, one hundred six billion, six hundred twenty-six million, three hundred thirteen thousand, five hundred fifty-five".

Divisors: 1 5 10821325262711 54106626313555