Base | Representation |
---|---|
bin | 11000100110101101011110… |
… | …01011110111010100000111 |
3 | 21002120112200220212112002211 |
4 | 30103112233023313110013 |
5 | 24042440400342310123 |
6 | 311024125342444251 |
7 | 14253035013643414 |
oct | 1423265713672407 |
9 | 232515626775084 |
10 | 54106642150663 |
11 | 16270552a33973 |
12 | 609a290b93687 |
13 | 24263081601bb |
14 | d50abdbb310b |
15 | 63c68803440d |
hex | 3135af2f7507 |
54106642150663 has 2 divisors, whose sum is σ = 54106642150664. Its totient is φ = 54106642150662.
The previous prime is 54106642150597. The next prime is 54106642150697. The reversal of 54106642150663 is 36605124660145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54106642150663 - 245 = 18922270061831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54106642180663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27053321075331 + 27053321075332.
It is an arithmetic number, because the mean of its divisors is an integer number (27053321075332).
Almost surely, 254106642150663 is an apocalyptic number.
54106642150663 is a deficient number, since it is larger than the sum of its proper divisors (1).
54106642150663 is an equidigital number, since it uses as much as digits as its factorization.
54106642150663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3110400, while the sum is 49.
The spelling of 54106642150663 in words is "fifty-four trillion, one hundred six billion, six hundred forty-two million, one hundred fifty thousand, six hundred sixty-three".
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