Base | Representation |
---|---|
bin | 11000100110110100001111… |
… | …10000000010010000110111 |
3 | 21002120220002010200100222012 |
4 | 30103122013300002100313 |
5 | 24043020321012330401 |
6 | 311025530054154435 |
7 | 14253224033001623 |
oct | 1423320760022067 |
9 | 232526063610865 |
10 | 54110275511351 |
11 | 162720479685a4 |
12 | 609ab25952a1b |
13 | 2426766b20b77 |
14 | d50d46568183 |
15 | 63c7ebed58bb |
hex | 313687c02437 |
54110275511351 has 4 divisors (see below), whose sum is σ = 54146811823104. Its totient is φ = 54073739199600.
The previous prime is 54110275511333. The next prime is 54110275511387. The reversal of 54110275511351 is 15311557201145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54110275511351 - 214 = 54110275494967 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54110275511299 and 54110275511308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54110275511311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18268153655 + ... + 18268156616.
It is an arithmetic number, because the mean of its divisors is an integer number (13536702955776).
Almost surely, 254110275511351 is an apocalyptic number.
54110275511351 is a deficient number, since it is larger than the sum of its proper divisors (36536311753).
54110275511351 is a wasteful number, since it uses less digits than its factorization.
54110275511351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36536311752.
The product of its (nonzero) digits is 105000, while the sum is 41.
The spelling of 54110275511351 in words is "fifty-four trillion, one hundred ten billion, two hundred seventy-five million, five hundred eleven thousand, three hundred fifty-one".
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