Base | Representation |
---|---|
bin | 1111101111111000100… |
… | …00001101100000000010 |
3 | 1220201200101210110202212 |
4 | 13313330100031200002 |
5 | 32331134333120114 |
6 | 1052325043342122 |
7 | 54044015532113 |
oct | 7677420154002 |
9 | 1821611713685 |
10 | 541103020034 |
11 | 199531603845 |
12 | 88a52381942 |
13 | 3c04489a7c5 |
14 | 1c2920b820a |
15 | e11e39ab3e |
hex | 7dfc40d802 |
541103020034 has 4 divisors (see below), whose sum is σ = 811654530054. Its totient is φ = 270551510016.
The previous prime is 541103019997. The next prime is 541103020091. The reversal of 541103020034 is 430020301145.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 497302808809 + 43800211225 = 705197^2 + 209285^2 .
It is a super-2 number, since 2×5411030200342 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 541103019991 and 541103020009.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 135275755007 + ... + 135275755010.
Almost surely, 2541103020034 is an apocalyptic number.
541103020034 is a deficient number, since it is larger than the sum of its proper divisors (270551510020).
541103020034 is a wasteful number, since it uses less digits than its factorization.
541103020034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 270551510019.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 541103020034 its reverse (430020301145), we get a palindrome (971123321179).
The spelling of 541103020034 in words is "five hundred forty-one billion, one hundred three million, twenty thousand, thirty-four".
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