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5411310455545 = 51082262091109
BaseRepresentation
bin100111010111110101100…
…1111001100101011111001
3201011022112112022011120221
41032233223033030223321
51202124330434034140
615301531031020041
71065645213643201
oct116575317145371
921138475264527
105411310455545
1117a6a18752585
127348b8b0a621
13303390a48a47
14149ca1b51401
1595b6208114a
hex4ebeb3ccaf9

5411310455545 has 4 divisors (see below), whose sum is σ = 6493572546660. Its totient is φ = 4329048364432.

The previous prime is 5411310455503. The next prime is 5411310455561. The reversal of 5411310455545 is 5455540131145.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1565871817104 + 3845438638441 = 1251348^2 + 1960979^2 .

It is a cyclic number.

It is not a de Polignac number, because 5411310455545 - 241 = 3212287199993 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541131045550 + ... + 541131045559.

It is an arithmetic number, because the mean of its divisors is an integer number (1623393136665).

Almost surely, 25411310455545 is an apocalyptic number.

It is an amenable number.

5411310455545 is a deficient number, since it is larger than the sum of its proper divisors (1082262091115).

5411310455545 is a wasteful number, since it uses less digits than its factorization.

5411310455545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1082262091114.

The product of its (nonzero) digits is 600000, while the sum is 43.

The spelling of 5411310455545 in words is "five trillion, four hundred eleven billion, three hundred ten million, four hundred fifty-five thousand, five hundred forty-five".

Divisors: 1 5 1082262091109 5411310455545