Base | Representation |
---|---|
bin | 100111010111110101100… |
… | …1111001100101011111001 |
3 | 201011022112112022011120221 |
4 | 1032233223033030223321 |
5 | 1202124330434034140 |
6 | 15301531031020041 |
7 | 1065645213643201 |
oct | 116575317145371 |
9 | 21138475264527 |
10 | 5411310455545 |
11 | 17a6a18752585 |
12 | 7348b8b0a621 |
13 | 303390a48a47 |
14 | 149ca1b51401 |
15 | 95b6208114a |
hex | 4ebeb3ccaf9 |
5411310455545 has 4 divisors (see below), whose sum is σ = 6493572546660. Its totient is φ = 4329048364432.
The previous prime is 5411310455503. The next prime is 5411310455561. The reversal of 5411310455545 is 5455540131145.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1565871817104 + 3845438638441 = 1251348^2 + 1960979^2 .
It is a cyclic number.
It is not a de Polignac number, because 5411310455545 - 241 = 3212287199993 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541131045550 + ... + 541131045559.
It is an arithmetic number, because the mean of its divisors is an integer number (1623393136665).
Almost surely, 25411310455545 is an apocalyptic number.
It is an amenable number.
5411310455545 is a deficient number, since it is larger than the sum of its proper divisors (1082262091115).
5411310455545 is a wasteful number, since it uses less digits than its factorization.
5411310455545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1082262091114.
The product of its (nonzero) digits is 600000, while the sum is 43.
The spelling of 5411310455545 in words is "five trillion, four hundred eleven billion, three hundred ten million, four hundred fifty-five thousand, five hundred forty-five".
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