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541131433 is a prime number
BaseRepresentation
bin100000010000010…
…000001010101001
31101201020022202221
4200100100022221
52102012201213
6125410154041
716260353443
oct4020201251
91351208687
10541131433
11258500067
12131282921
138815691b
1451c21493
153279038d
hex204102a9

541131433 has 2 divisors, whose sum is σ = 541131434. Its totient is φ = 541131432.

The previous prime is 541131413. The next prime is 541131449. The reversal of 541131433 is 334131145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 523128384 + 18003049 = 22872^2 + 4243^2 .

It is a cyclic number.

It is not a de Polignac number, because 541131433 - 229 = 4260521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 541131398 and 541131407.

It is not a weakly prime, because it can be changed into another prime (541131413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270565716 + 270565717.

It is an arithmetic number, because the mean of its divisors is an integer number (270565717).

Almost surely, 2541131433 is an apocalyptic number.

It is an amenable number.

541131433 is a deficient number, since it is larger than the sum of its proper divisors (1).

541131433 is an equidigital number, since it uses as much as digits as its factorization.

541131433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2160, while the sum is 25.

The square root of 541131433 is about 23262.2319006582. The cubic root of 541131433 is about 814.8936255710.

Adding to 541131433 its reverse (334131145), we get a palindrome (875262578).

The spelling of 541131433 in words is "five hundred forty-one million, one hundred thirty-one thousand, four hundred thirty-three".