Base | Representation |
---|---|
bin | 111101100001010000010010… |
… | …0000111101011100110100111 |
3 | 2121221222201121020110111200112 |
4 | 1323002200210013223212213 |
5 | 1031411402043120113030 |
6 | 5154520355553403235 |
7 | 221660335345440515 |
oct | 17302404407534647 |
9 | 2557881536414615 |
10 | 541132125551015 |
11 | 14746a933651899 |
12 | 50837045b6951b |
13 | 1a2c37045945ab |
14 | 978ad128654b5 |
15 | 428614d607a95 |
hex | 1ec28241eb9a7 |
541132125551015 has 16 divisors (see below), whose sum is σ = 652990175877600. Its totient is φ = 430484646029952.
The previous prime is 541132125551011. The next prime is 541132125551063. The reversal of 541132125551015 is 510155521231145.
It is a cyclic number.
It is not a de Polignac number, because 541132125551015 - 22 = 541132125551011 is a prime.
It is a super-2 number, since 2×5411321255510152 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (541132125551011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 154742789 + ... + 158201121.
It is an arithmetic number, because the mean of its divisors is an integer number (40811885992350).
Almost surely, 2541132125551015 is an apocalyptic number.
541132125551015 is a deficient number, since it is larger than the sum of its proper divisors (111858050326585).
541132125551015 is a wasteful number, since it uses less digits than its factorization.
541132125551015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3633346.
The product of its (nonzero) digits is 150000, while the sum is 41.
The spelling of 541132125551015 in words is "five hundred forty-one trillion, one hundred thirty-two billion, one hundred twenty-five million, five hundred fifty-one thousand, fifteen".
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