Base | Representation |
---|---|
bin | 111101100001010000010010… |
… | …0000111101011101001100011 |
3 | 2121221222201121020110111221111 |
4 | 1323002200210013223221203 |
5 | 1031411402043120114303 |
6 | 5154520355553404151 |
7 | 221660335345441204 |
oct | 17302404407535143 |
9 | 2557881536414844 |
10 | 541132125551203 |
11 | 14746a933651a4a |
12 | 50837045b69657 |
13 | 1a2c37045946c4 |
14 | 978ad128655ab |
15 | 428614d607b6d |
hex | 1ec28241eba63 |
541132125551203 has 2 divisors, whose sum is σ = 541132125551204. Its totient is φ = 541132125551202.
The previous prime is 541132125551179. The next prime is 541132125551257. The reversal of 541132125551203 is 302155521231145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 541132125551203 - 29 = 541132125550691 is a prime.
It is not a weakly prime, because it can be changed into another prime (541132125557203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270566062775601 + 270566062775602.
It is an arithmetic number, because the mean of its divisors is an integer number (270566062775602).
Almost surely, 2541132125551203 is an apocalyptic number.
541132125551203 is a deficient number, since it is larger than the sum of its proper divisors (1).
541132125551203 is an equidigital number, since it uses as much as digits as its factorization.
541132125551203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180000, while the sum is 40.
Adding to 541132125551203 its reverse (302155521231145), we get a palindrome (843287646782348).
The spelling of 541132125551203 in words is "five hundred forty-one trillion, one hundred thirty-two billion, one hundred twenty-five million, five hundred fifty-one thousand, two hundred three".
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