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541132125551219 = 3111739974680229
BaseRepresentation
bin111101100001010000010010…
…0000111101011101001110011
32121221222201121020110111222002
41323002200210013223221303
51031411402043120114334
65154520355553404215
7221660335345441226
oct17302404407535163
92557881536414862
10541132125551219
1114746a933651a64
1250837045b6966b
131a2c3704594707
14978ad128655bd
15428614d607b7e
hex1ec28241eba73

541132125551219 has 4 divisors (see below), whose sum is σ = 542872100231760. Its totient is φ = 539392150870680.

The previous prime is 541132125551203. The next prime is 541132125551257. The reversal of 541132125551219 is 912155521231145.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 541132125551219 - 24 = 541132125551203 is a prime.

It is a super-2 number, since 2×5411321255512192 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (541132125251219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 869987339804 + ... + 869987340425.

It is an arithmetic number, because the mean of its divisors is an integer number (135718025057940).

Almost surely, 2541132125551219 is an apocalyptic number.

541132125551219 is a deficient number, since it is larger than the sum of its proper divisors (1739974680541).

541132125551219 is a wasteful number, since it uses less digits than its factorization.

541132125551219 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1739974680540.

The product of its digits is 540000, while the sum is 47.

The spelling of 541132125551219 in words is "five hundred forty-one trillion, one hundred thirty-two billion, one hundred twenty-five million, five hundred fifty-one thousand, two hundred nineteen".

Divisors: 1 311 1739974680229 541132125551219