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54113360044129 is a prime number
BaseRepresentation
bin11000100110111001111111…
…00110100110000001100001
321002121012001002202212110221
430103130333212212001201
524043043130132403004
6311031200122323041
714253363336046561
oct1423347746460141
9232535032685427
1054113360044129
1116273390015741
12609b646959481
132426b38b919a9
14d5115a096da1
1563c92cbc6354
hex31373f9a6061

54113360044129 has 2 divisors, whose sum is σ = 54113360044130. Its totient is φ = 54113360044128.

The previous prime is 54113360044061. The next prime is 54113360044147. The reversal of 54113360044129 is 92144006331145.

54113360044129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40500750560400 + 13612609483729 = 6364020^2 + 3689527^2 .

It is a cyclic number.

It is not a de Polignac number, because 54113360044129 - 241 = 51914336788577 is a prime.

It is not a weakly prime, because it can be changed into another prime (54113360044189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27056680022064 + 27056680022065.

It is an arithmetic number, because the mean of its divisors is an integer number (27056680022065).

Almost surely, 254113360044129 is an apocalyptic number.

It is an amenable number.

54113360044129 is a deficient number, since it is larger than the sum of its proper divisors (1).

54113360044129 is an equidigital number, since it uses as much as digits as its factorization.

54113360044129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 54113360044129 in words is "fifty-four trillion, one hundred thirteen billion, three hundred sixty million, forty-four thousand, one hundred twenty-nine".