Base | Representation |
---|---|
bin | 1111101111111100001… |
… | …11001010001000001011 |
3 | 1220201202120110122111121 |
4 | 13313332013022020023 |
5 | 32331220323420410 |
6 | 1052332115540111 |
7 | 54044544550546 |
oct | 7677607121013 |
9 | 1821676418447 |
10 | 541134201355 |
11 | 199548170830 |
12 | 88a608ba637 |
13 | 3c04b1973a7 |
14 | 1c2962b385d |
15 | e121ea99da |
hex | 7dfe1ca20b |
541134201355 has 16 divisors (see below), whose sum is σ = 725671765728. Its totient is φ = 383953312000.
The previous prime is 541134201301. The next prime is 541134201371. The reversal of 541134201355 is 553102431145.
It is not a de Polignac number, because 541134201355 - 213 = 541134193163 is a prime.
It is a super-2 number, since 2×5411342013552 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 541134201355.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 119983156 + ... + 119987665.
It is an arithmetic number, because the mean of its divisors is an integer number (45354485358).
Almost surely, 2541134201355 is an apocalyptic number.
541134201355 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
541134201355 is a deficient number, since it is larger than the sum of its proper divisors (184537564373).
541134201355 is a wasteful number, since it uses less digits than its factorization.
541134201355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 239970878.
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 541134201355 in words is "five hundred forty-one billion, one hundred thirty-four million, two hundred one thousand, three hundred fifty-five".
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